If you need find the angle on the xy plane. Let's use the point (2, 3, 13) here the gradient is =. Now, you will have a point (x,y,z) on a graph of f(x,y) the gradient says at point (x,y,z) if you rotate yourself to face the vector you get from the gradient at that point, if you proceed forward the rate of change relative to the z axis will be the greatest in that direction. This vector is going to be parallel to the xy axis. The gradient gives us a vector, specifically a 2D vector. Let me emphasize my question: Do you agree with me that we all should make better use of this site and its possibilities? Do you agree with me that we all should make better use of this site and its possibilities? In the near future I hope to comment on some of your questions (please don’t take offense!) and I will problably pose some questions myself. Let’s try to change that! Hope you don’t find me presumptuous. Unfortunately I see very few well-formulated clear questions some posts are not even questions at all! No wonder that you (we!) get little or no response. Khan Academy makes it very clear that it hopes (rather: expects) that we are teaching each other. (it’s almost 50 years ago that I was taught this stuff it’s a trip down memory lane for me I have to refresh it all and that will take me some time). I just started with “multivariable calculus” and I was curious whether I could be of some help (and get some help!) on this forum. I am relatively new to Khan Academy and I like it a lot!
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